In each of the scenarios below, two spheres of the same size and shape hang from

Question

In each of the scenarios below, two spheres of the same size and shape hang from a common attachment joint. Each sphere is electrically charged and is either perfectly conductive or perfectly insulating, as indicated in the key below. The magnitude of charge Q is greater than the magnitude of charge q. Each pair of spheres is allowed to swing freely and comes to rest in some equilibrium position. In each scenario, determine whether the spheres come to rest in contact, or separated by some distance. Assume that the weight of the spheres is small enough that electrostatic forces are significant. A 2.00-gram air inflated balloon is given an excess negative charge, q_1 = -4.00 times 10^-8 C, by rubbing it with a blanket. It is found that a charged rod can be held above the balloon at a distance of d = 8.00 cm to make the balloon float. In order for this to occur, what polarity of charge must the rod posses?? How much charge, q_2, does the rod have? Assume the balloon and rod to be point charges. The Coulomb force constant is 1/(4 pi epsilon_0) = 8.99 times 10^8 N. m^2/C^2 and the acceleration due to gravity 9.81 = m/s^2. q_2 is positive proton neutral negative Two charges are located in the x-y plane. If q_1 = -3.95 nC and is located at x = 0.00 m, y = 1.080 m and the second charge has magnitude of q_2 = 3.40 nC and is located at x = 1.10 m, y = 0.550 m, calculate the x and y components, E_x and E_y, of the electric field, E rightarrow, in component form at the origin, (0,0). The Coulomb Force constant is 1/(4 pi epsilon_0) = 8.99 times 10^9 N. m^2/C^2. Using the symmetric of the arrangement, determine the direction of the force on q in the figure below, given that q_a = q_0 = +7.55 mu C, q_c = q_d = -7.55 mu C, and q is positive. up and left up and right down and left left down and right right up down Calculate the magnitude of the force on the charge q, given that the square is 10.90 cm on a side and q = 1.75 mu C. A pair of closely spaces parallel conducting plates, charged with equal and opposite electric charges, produces a uniform electric field in the region between them. In designing a cutting-edge device that will revolutionize the electronics industry, you set up such a pair of plates with a separation of 0.997 mm between them and charge them so that the direction of the electric field in their interior region is from plate A to plate B. Your idea requires that electrons, when released from rest at one of the plates, reach the other plate at the speed of 1.35% of the speed of light. (The speed of light is c = 3.00 times 10^8 m/s.) At which plate should the electrons be released? A B Either Cannot be determined A finite line of charge with linear charge density lambda = 3.65 times 10^-6 C/m, and length L = 0.786 m is located along the x axis(from X = 0 to X = L).A point charge of q = -7.32 times 10^-7 C is Seated at the point X_0 = 1.28 m, Y_0 = 4.50 m. Find the electric field (magnitude and direction as measured from the +x axis) at the point P which is located along the x axis at X_P = 12.3 m. The Coulomb force constant k = 1/(4 pi epsilon_0) = 8.99 times 10^9 N. m^2/C^2. E = N/C theta = degree

Explanation / Answer

2.

It has to be an attractive force, which means opposite charges, so the rod has to have a + charge.

Coulomb's law, force of attraction/repulsion
F = kQQ/r²
Q and Q are the charges in coulombs
F is force in newtons
r is separation in meters
k = 8.99e9 Nm²/C²

The electrostatic force must equal the force of graviey, which is w = mg = 0.002 x 9.81

0.002*9.81 = [{8.99*(10)*4*(10)*q}/{(0.08)²}] or
q = [(0.002*9.81){(0.08)²}]*/(8.99*40) = 3.49*10 C or 349 nC

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.