The work required to stretch a spring 2 cm from its natural length is Double the
ID: 1571737 • Letter: T
Question
The work required to stretch a spring 2 cm from its natural length is Double the work required to stretch it 1 cm from its natural length. 4 times the work required to stretch it 1 cm from its natural length. The same as the work required to stretch 1cm it from its natural length because this is work applied from outside. None of the above, my answer is_ Two friends decided to ascend a mountain. John chooses a short, steep trail, while Simon, who weighs the same as John, goes up via a long gently sloped trail. At the top, they argue who gained more potential energy. Which of the following is true? John gains more gravitational potential energy than Simon. John gains less gravitational potential energy than Simon. John gains the same gravitational potential energy as Simon. We must know the height of the mountain. We must know the length of the two trails. Consider an object that is falling from rest. It accelerates downward with the gravitational acceleration g. As the object gains speed, the drag force decreases. At the point when the drag force and gravity have equal magnitude, the object falls with a constant speed called the terminal speed. The drag force is always constant and determined by the shape of the object. When the net force on the object is zero, it falls with the constant terminal speed. Both (b) and (d) are correct. None of the above. Weight in an elevator: A person weighs a fish of mass m on a spring scale in an elevator that is going down. If the apparent weight of the fish outside the elevator is 40.0 N and the apparent weight inside the elevator is 48.2 N, then that means The elevator was accelerating downward with an acceleration 2.0 m/s^2 The elevator was coming to a stop with an acceleration of - 2.0 m/s^2 The spring scale is not accurate because it gives a reading that is different from the weight of the fish. None of the above, my answer is_Explanation / Answer
1) Option b , because work required is 1/2 k x^2 so when x=2 squre becomes 4 times of when x is one
2) option c , as Energy= mgh ( same maas, same height is given , g is constant anyway )
3) option e
4) mg-N= ma
40-48.2= 4.08 a
a= - 2.0 m/s^2 , Option b
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