1.You drive 7.50 km in a straight line in a direction 25° East of North.(a) Find
ID: 1571808 • Letter: 1
Question
1.You drive 7.50 km in a straight line in a direction 25° East of North.(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
2. Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts a force of 75.0 N, the second a force of 95.0 N, friction is 12.0 N, and the mass of the third child plus wagon is 24.0 kg.
(a) What is the system of interest if the acceleration of the child in the wagon is to be calculated? (Select all that apply.)
the child in the wagonthe children outside the wagonthe wagon
(c) Calculate the acceleration.
m/s2
(d) What would the acceleration be if friction is 20.0 N?
Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 10,300 kg. The thrust of its engines is 33,000 N. (Assume that the gravitational acceleration on the Moon is 1.67 m/s2.)
(a) Calculate its magnitude of acceleration in a vertical takeoff from the Moon.
m/s2
Explanation / Answer
1. Take the component of vector in x and y direction
X component- 75cos25 =67.97 km. ( east)
Y component - 75 sin 25 = 31.69 km ( north)
2.)
A.)The wagon because whatever acceleration of the wagon would be same is the child.
C.)
Net force = 95-75 =20N
F=ma
20-12 = 24*a
a= 0.333m/s^2
D) net force become zero so acceleration would be zero
A) F = ma-mg
33000 = 10,300a + 10300*1.67
a = 1.53 m/s^2
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