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niversity physics T-SP1 Paulius Chrome Google ch.edu/d21/le/content/250797/viewContent/2128915Niew PHYS2050 Universit... Reda Ali A 0/1 point If we are given a graph which shows a plot of the position as a function of time, x(), how wil the instantaneous velocity at point C be related to the graph? A) it would equal the slope of the line tangent to curve at point B the x(t) B) it would equal the slope of the line tangent to the x() curve at point C c) it would equal the slope of the line between points B and c on the x(t) curve D) it would equal the absolute value of the slope of the line tangent to the x(t) curve at c point Question 14 0 1 point If we are given a graph which shows a plot of the position as a function of xt, how will the instantaneous sneed at point c be related to the graph? time, A) it would equal the slope of the line tangent to the x(t) curve at point B B) it would equal the slope of the line tangent to the x(t) curve at point c c) it would equal the slope of the line between points B and Con the x(t) curve D) it would equal the absolute value of the slope of the line tangent to the x curve at point c Activity Details (9 Starts Jan 12, 2017 10 oo AM Ends van 15, 2017 11:59 PM

Explanation / Answer

Question 002) 1 in^3 = 1.639*10^-5 m^3

So 6.97 in ^3

= 6.97*1.639*10^-5

= 11.42383 * 10^-5 m^3

Question 003)

From the calculations we get 1 ft = 0.305 m and 1 in = 0.0254 m

So 502 ft = 502 * .305 = 153.11 m

And 9 in = 9 * 0.0254 = 0.2286 m

502ft 9in = 153.11 + 0.2286 = 153.3386 m

Question 004) since 1 metric ton = 1000 kg

205 metric tons = 205 *1000 = 205000 kg

If one person pulls 90 kg

Number of persons required = 205000/90 = 2278 people

Question 005) 1 million pounds = 453592.37 kg

4.5 million pounds = 4.5*453592.37 = 2041165.665 kg

Number of people required to move = 2041165.665/90 = 22680 people

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