The student gave this solution: (9.0×109Nm2/C2)(+2.0×104C)(+1.0×104C)/(0.40m)2 =

Question

The student gave this solution: (9.0×109Nm2/C2)(+2.0×104C)(+1.0×104C)/(0.40m)2 =(1/2)(10kg)v2y+(0.20kg)(9.8m/s2)(10m) Evaluate the solution to this problem and check all errors you find. What are the errors? The options are 1.Electric potential energy in the first line is not correct. 2.Gravitational potential energy in the second line misses a square for the last factor. 3. The equation left out the electric potential energy in the second line. 4. The equation left out the gravitational potential energy in the first line.

Explanation / Answer

the formula for electric potential energy is

k Q1 Q2/r

so the formula does not have a square at the denominator,

1.Electric potential energy in the first line is not correct.

so correct form will be like

(9.0×109Nm2/C2)(+2.0×104C)(+1.0×104C)/(0.40m) =(1/2)(10kg)v2y+(0.20kg)(9.8m/s2)(10m)

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