This print-out should have 17 questions. Multiple-choice questions may continue

Question

This print-out should have 17 questions. Multiple-choice questions may continue on the next column or page find all choices before answering PLEASE READ These questions cover material from chapters 1 and 2 2 The due date/time is Saturday January 21st at 8.00pm (central time) 3 Solutions available one hour later. [4] Numerical answers MUST be within 1% to score 001 5.0 points Consider position L, time tl T, ve- locity v L/T and acceleration la L/T Find the exponent A in the equation 2 A a t 1. 4 2. 2 4.3 002 8.0 points ML A certain force with units of measure is T2 given by the equation K ML2 where M is a mass, Lis a length, T is a time and K is a constant What are units of the constant K? M2 L2 1. LKI T6 2. [K] 3. Kl ML 4. [K] M2 L2 ML 5. [K] 6. 003 10.0 points Identify the equation below which is dimen- sionally incorrect. A, a, y and r have units of length. k here has units of inverse length. vo and v have units of velocity. a and g have units of acceleration. w has units of inverse time. t is time, m is mass, V is volume, p is density, and F m a is force TF wt) 2-2 4. vo rg g V 6. g tw A2 2 a a 8. t a t 004 5.0 points An automobile tire is rated to last for 80000 mi Estimate the number of revolutions the tire will make in its lifetime. Assume the diameter of the tire is 2.5 ft Answer in units of rev 005 10.0 points In May 1998, forest fires in southern Mexico and Guatemala spread smoke all the way to Austin. Those fires consumed forest land at a rate of 26800 acres/week. On the average, how many square meters of forest are burned down every minute? An

Explanation / Answer

Q1. LHS=L/T

RHS=(L/T^2)^2*T^A/L

=L*T^(A-4)

comparing exponent of T in LHS and RHS.

A-4=-1

==>A=3

hence option 4 is correct.

Q2.

LHS=M*L/T^2

RHS=K*M*L^2/T^4

equating LHS and RHS,

K=(M*L/T^2)*T^4/(M*L^2)

=T^2/L

option 6 is correct.

Q3.

option 5 is incorrect.

Q4. 80000 mile=1.28748*10^8 m

diameter=2.5 ft=0.762 m

then distance travelled in 1 revolution=circumference of the tyre

=pi*diameter=2.39389 m

so number of revolutions=1.28748*10^8/(2.39389)=5.378*10^7 revolutions

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