A thin, round disk made of acrylic plastic (density is 1.1 g/cm 3 ) is 20 cm in

Question

A thin, round disk made of acrylic plastic (density is 1.1 g/cm3) is 20 cm in diameter and 3 cm thick (see figure below). A very small hole is drilled through the disk at a point 8 cm from the center. The disk is hung from the hole on a nail and set into simple harmonic motion with a maximum angular displacement (measured from vertical) of 7°. Calculate the period of the motion.

2. 0/2 points I Previous Answers FRKestenCP1 12.P.060 My Notes A thin, round disk made of acrylic plastic (density is 1.1 g/cm) is 20 cm in diameter and 3 cm thick (see figure below), A very small hole is drilled through the disk at a point 8 cm from the center. The disk is hung from the hole on a nail and set into simple harmonic motion with a maximum angular displacement (measured from vertical) of 7°. Calculate the period of the motion 1.038 li 8 cm 1701 A hole is drilled through a thin, round disk of mass M and radius R = 0.10 m. The hole is located h 0.08 m from the center of mass of the disk. The disk is hung on a nail and set into simple harmonic motion. The period of a physical pendulum is related to the moment of inertia of the pendulum. Since the center of mass of the disk is located a distance h from the pivot point, we will need to use the paralel-ai theorem. As a reminder, the moment of inertia of a thin disk is eBook

Explanation / Answer

formula for period of pendulum is

T = 2 pi sqrt I/ mgd

from the parallel axix theorem the moment of inertia of disk is

I = I_cm + mh^2

= mR^2/2 + mh^2

= m( R^2/2 + h^2)

T = 2 pi sqrt  m( R^2/2 + d^2)/ mgh

=2 pi sqrt ( 0.10)^2 /2+ ( (0.08)^2/ (9.8) ((0.08)

=0.757 s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.