(- Assignment Submission For this assignment, you submit answers by queston part
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(- Assignment Submission For this assignment, you submit answers by queston parts The numbot of subonisions romaining for each quesation part onl changes f you submit or Not secure www.webassign net/web Student Assignment Responses subintider-17 15406 Assignment Scoring if you submit or cha Your last submission is used for your score. 1. An amoeba has 1.55 × 10 16 protons and a net charge of 0.790 pc. (a) How many fewer electrons are there than protons? X electrons Enter a number (b) If you paired them up, what fraction of the protons would have no electrons? protons without electrons protons Additional Materials ReadingExplanation / Answer
From the given question.
a)Number of protons= 1.55*10^16 =np
Number of electrons= ne
net charge=0.790 pC = (np-ne)*1.6*10^-19
np-ne=(0.79*10^-12)/(1.6*10^-19)
solving we get, np-ne=4937500
There are 4937500 fewer electrons.
b) protons without electrons/ protons= (4937500 )/(1.55*10^16)=1:(3.14*10^9)
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