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iPad 8:30 PM 26%. edugen.wileyplus.com Comparison | T...Log in to AuPair... Stila I Ulta Beau...Cracker Barrel... Home - myACU Quizzes WileyPLUS WileyPLUS WileyPLUS: MyWileyPLUSI Help Contact Us Log Out WileyPLUS cutnel, Physics, 10e GENERAL PHYSICS I & II (PHYS 110/112) Home Read, Study& Practice Gradebook ORION Downloadable eTextbook AssignmentOpen Assignment MESSAGE MY INSTRUCTOR FULLSCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 18, Problem 07 HW 18-1 Water has a mass per mole of 18.0 g/mol, and each water molecule (H20) has 10 electrons. (a) How many electrons are there in 6.23 liters of water? (1 liter is equivalent to 1.00 x 103 m3) (b) What is the net charge of all these electrons? (a) Number (b) Number Show Work is REQUIRED for this question: enShow work GO Units Review Score Review Results by Study Objective LINK TO TEXT LINK TO TEXT LINK TO TEXT LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your Question Attempts: 0 of 4 used SAVE FOR LATER SUB MIT ANSWER Earn Maximum Points available only if you answer this question correctly in three attempts or less.Explanation / Answer
a] Number of electrons, N
= 6.23L*(1*10^-3)m^3/L* (1*10^6)g/m^3 * (1/18)mol/g * 6.02*10^23 molecules/mol * 10 electrons/molecules
= 2.08*10^27 electrons
b] Net charge, q = Ne
= 2.08*10^27 *(-1.6*10^-19) C
= -3.328*10^8 C
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