INTERNET STATION PLEASE SIGN-IN FIRST BEFORE USING THE COMPUTERS h Module Three

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INTERNET STATION PLEASE SIGN-IN FIRST BEFORE USING THE COMPUTERS h Module Three x C www.webassignnet/weltu/Student/Assignment Responsestest dep 1767950 i Facebook Army Knowledge O A contestant in a winter games event pulls a 41.0 kg block of ice across a frozen lake with a rope over his s 4.29(b). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03 Other boo Figure 4.29 (a) Calculate the minimum force F he must exert to get the block moving. (b) What is its acceleration once it starts to move, if that force is maintained? nvs? Additional Materials asqurel with a surface area of rrons n .:m tree to The ground. Estimate its termini vet PRINTER 1

Explanation / Answer

Initially, force requires is sufficient only to move it, so

The normal force here is Fn = m*g + Fsin25º

Or, F = 41kg * 9.8m/s² +0.4226F = 402N + 0.4226F

Now,

The net horizontal force is F =Fcos25 -µs*Fn

Or, Fh = Fcos25º- 0.1(402N+ 0.4226F)

Or, Fh= 0.9063F- 40.2N - 0.04226F

Or, Fh= 0.864F - 40.2 N

For (a) when minimum force is required to move it, this horizontal force is zero , or,

Fh = 0

or, F = 40.2N / 0.864

or, F= 46.5 N

minimum force is required to move it is F= 46.5 N

(b) Now, Fh = 46.5N*cos25º - 0.03(402N + 0.4226*46.5) {since friction is now kinetic not static}

Or, Fh= 29.5 N

Or, acceleration = a = Fh / m = 0.72 m/s²

so, acceleration a= 0.72 m/s²

please upvote if understood to appreciate

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