Problem 3 a) Two point-like particles are placed 46.6 cm apart and are given equ

Question

Problem 3 a) Two point-like particles are placed 46.6 cm apart and are given equal and opposite charge. The first particle, of mass 16.0 g, has an initial acceleration of 7.95 m/s towards the second particle. What is the mass of the second particle if its initial acceleration towards the first is 7.20 m/s? 17667 g You are correct. Computer's answer now shown above Your receipt is 163-2985 b) What is the magnitude of the charge on each particle? 5.54c-5C Submit Answer Incorrect. Tries 2/6 Previous Tries

Explanation / Answer

From Coulomb's Law

F = k*q^2/r^2 (assuming equal charges) ..

So q = sqrt(F*r^2/k) = sqrt(m1*a1*r^2/k) =

sqrt(0.016kg*7.95m/s^2*(0.466m)^2/9.0x10^9= 1.750x10^-6C = 1.75C

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