Interactive Solution 20.47 provides one approach to problems like this one. Thre

Question

Interactive Solution 20.47 provides one approach to problems like this one. Three resistors are connected in series across a battery. The value of each resistance and its maximum power rating are as follows: 6.2 and 22.7 W, 33.8 and 12.7 W, and 14.7 and 10.1 W. (a)What is the greatest voltage that the battery can have without one of the resistors burning up? (b) How much power does the battery deliver to the circuit in (a)?

*** The answers are not 20.5, 7.70, 44.766,45.5** these have already been given to me and are incorrect

Explanation / Answer

The net resistance of the circuit = 6.2 + 33.8 + 14.7 = 54.7 ohms

Let the voltage be V.

So, the current in the circuit is V/54.7

Power across 10.1 W resistor , P = I^2 R = 10.1

V^2 / 54.7 = 10.1

V = 23.5 Volts

The maximum battery voltage can be : 23.5 V

(b) The current = V/R = .43 Amps

Power across all resistors = .43^2 (54.7) = 10.1 W

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.