Problem 1 Two 2.40-cn-diameter disks spaoed 2.00 uuu apart form a parallel plate

Question

Problem 1 Two 2.40-cn-diameter disks spaoed 2.00 uuu apart form a parallel plate capacitor. The electric tieid between the disks is 5.20 105 Vim PartA What is the yaltage acrss the capacitor? Express your answer to two significant figures and include the appropriate units. Submit Request Anaxer Part B An electron is launched from the negative plate. It strkes the posilive plate at a soced of 2.2010 m/s. What was the electron's spocd as it left the negative plate? Express your answer to two significant figures and include the appropriate units. alu m/s Submit

Explanation / Answer

(A) V = Ed

= (5.20 x 10^5 V/m) (2 x 10^-3 m )

= 1040 Volt ........Ans

(B) electric force, Fe = q E toward +ve plate

acceleration, a = Fe / m = q E / m toward positive plate

a = (1.6 x 10^-19 x 5.20 x 10^5) / (9.109 x 10^-31)

a = 9.134 x 10^16 m/s^2

vf^2 - vi^2 =2 a d

(2.20 x 10^7)^2 - v^2 = 2(9.134 x 10^16) (2 x 10^-3)

v = 1.09 x 10^7 m/s ........Ans

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