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fari File Edit View History Bookmarks Window Help 11%D Sat 7:52 PM a E edugen.wileyplus.com Solved: In Section 8.6, it was asserted that the sum of all the... Chegg.com Google Translate WileyPLUS: MyWilleyPLUS I Help | Contact WileyPLUS taliday, Fundamentals of Physics, 10 GENERAL PHYSICS 1 & 2 (GENERAL PHYSICS 1 & 2) Home R ad, Study & Practice Gradebook ORION Downloadable eTextbook Assignment> Open Assignment FULL SCREEN PRINTER VERSION BACK ASSIGNMENT RESOURCES Chapter 21, Problem 062 After Class Assignment e202 Asinmn In the figure what are the (a) magnitude and (b)direction (from x-axis in the counterclockwise direction) of the net electrostatic force on particle 4 due to the other three particles? All four particles are fixed in the xy plane, and q1 =-22.40% 10-19 C, q2° +22.40 × 10-19 C, q3 = +44.80 x 10-19 C, q4 = +22.40 x 10-19 C, | = 42°, d1 = 3.70 cm, and d2 = d3 = 3.10 cm. Chapter 21, Problem l Chapter 21 Problem 011 (Vector Drawing) Chapter 21, Problem (a) Number Units Units Chapter 21, Problem LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLEPfOBLEM MATH HELP MATH HELp Chapter 21. Problerm Question Attempts: 0 of 3 used SAVE FOR LATER SUBMIT ANSWER Agreement1 Privacy Policy I 2000-2018 John Wiley &Sons;, Inc. All Rights Reserved. A Division of John Wiley & Sons,Inc Version 4.24.4.5 1263 12 NExplanation / Answer
a) |F14| = k*q1*q4/d1^2
= 9*10^9*22.4*10^-19*22.4*10^-19/0.037^2
= 3.29*10^-23 N
|F24| = k*q2*q4/d2^2
= 9*10^9*22.4*10^-19*22.4*10^-19/0.031^2
= 4.70*10^-23 N
|F34| = k*q3*q4/d2^2
= 9*10^9*44.8*10^-19*22.4*10^-19/0.031^2
= 9.40*10^-23 N
Fx = -F14*cos(42) - F34
= -3.29*10^-23*cos(42) - 9.40*10^-23
= -1.18*10^-22 N
Fy = -F14*sin(42) - F24
= -3.29*10^-23*sin(42) - 4.70*10^-23
= -6.90*10^-23 N
Fnet = sqrt(Fx^2 +Fy^2)
= sqrt(1.18^2 + 0.690^2)*10^-22
= 1.37*10^-22 N <<<<<<--------------------Answer
b) direction : theta = tan^-1(Fy/Fx)
= tan^-1(0.69/1.18)
= 30.3 degrees with -x axis
= 210.3 degrees with +x axis in counterclockwise direction.
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