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E PHYS 4A Homework 2 xy d WileyPLUS × e A Plane Flies 400 Km East Frc × uu Mathw

ID: 1573810 • Letter: E

Question

E PHYS 4A Homework 2 xy d WileyPLUS × e A Plane Flies 400 Km East Frc × uu Mathway 1 Math Problem Solv x Inverse Trigonometric Functio x csecure https://edugen.wileyplus.com/edugen/lti/main.uni Halliday, Fundamentals of Physics, 10e BACK NEXT ASSIGNMENT RESOURCES Chapter 04, Problem 032 Ch. 3,4 003 009 072 In the figure, you throw a ball toward a wall at speed 28.0 m/s and at angle = 40.0° above the horizontal. The wall is distance d 21.0 m from the release point of the ball (a) How far above the release point does the ball hit the wall? What are the (b) horizontal and (c) vertical components of its velocity as it hits the wall? 6 023 008 015 (a) Number (b) Number (e) Number Click if you would like to Show Work for this question: Unit Unit Unit hapter 04, Probler 041 Revlew Results by Stud Open Show Work LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE MATH HELP MATH HELP https://edugen.wileyplus.com/ed ugen/shared/ assignment/test/agli st.uni?id_asnmt 20444 38#N100B2

Explanation / Answer

here,

intial speed , u = 28 m/s

theta = 40 degree

x = 21 m

a)

the vertical height of the ball , y = x * tan(theta) - g * x^2 / ( 2 * v^2 * cos^2(theta))

y = 21 * tan(40) - 9.81 * 21^2 /( 2 * 28^2 * cos^2(40))

y = 12.9 m

b)

the horizontal speed , vx = u * cos(theta)

vx = 28 * cos(40) = 21.4 m/s

c)

let the vertical speed be vy

vy^2 - uy^2 = 2 * g * y

vy^2 - (28 * sin(40))^2 = 2 * 9.81 * 12.9

solving for vy

vy = 24 m/s