6 O -5 points SerCP11 16.P019 My A proton is located at the origin, and a second

Question

6 O -5 points SerCP11 16.P019 My A proton is located at the origin, and a second proton Is located on the x-axis at xi- 5.98 fm ( fm - 10-15 m). (a) Calculate the electric potential energy associated with this configuration. (b) An alpha particle (charge-2e·mass-6.64 x 10-27 kg) is now placed at potential energy associated with this conriguration. n-a99, 2 99) m. caenate the 2) (2.99, 2.99) fm. Calculate the electric resistance of a wo resistors (c) Starting with the three particle system, find the change in electric potential energy if the alpha particle is ailowed to escape to Infinity while the two protons remain fixed in plece. (Throughout, neglect any radiation effects.) (d) Use conservation of energy to calculate the speed of the alpha particle at infinity TVs (e) If the two protons are released from rest and the alpha particle remains fixed, calculate the speed of the protons at infinity. m/s Need Help? Rese My Notss Ask Your Tea

Explanation / Answer

(A) PE = k q1 q2 / r

= (9 x 10^9) (1.6 x 10^-19)^2 / (5.98 x 10^-15)

= 3.86 x 10^-14 J

(B) Pe = (3.86 x 10^-14) + 2(9 x 10^9 x 2 x (1.6 x 10^-19)^2 / sqrt(2.99^2 + 2.99^2) x 10^-15)

PE = 2.565 x 10^-13 J

(C) change in PE = PEf - PEi = 3.86 x 10^-14 - 2.565 x 10^-13

= - 2.179 x 10^-13

(D) Decrease in PE = gain in KE

2.179 x 10^-13 = (6.64 x 10&-27) v^2 / 2

v = 8.10 x 10^6 m/s

(E)
2.565 x 10^-13 = 2(1.67 x 10^-27) v^2 / 2

v = 1.24 x 10^7 m/s

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