A pair of closely spaced parallel conducting plates, charged with equal and oppo

Question

A pair of closely spaced parallel conducting plates, charged with equal and opposite electric charges, produces a uniform electric field in the region between them. In designing a cutting-edge device that will revolutionize the electronics industry, you set up such a pair of plates with a separation of 0.897 mm between them and charge them so that the direction of the electric field in their interior region is from plate A to plate B. Your idea requires that electrons, when released from rest at one of the plates, reach the other plate at the speed of 1.85% of the speed of light. (The speed of light is c-3.00 x 108 m/s.) At which plate should the electrons be released? O Either Cannot be determined What must the strength of the electric field be? Number N/C

Explanation / Answer

electron have to be released from negative charged plate as it will be attracted by +ve plate and repelled by negative charged plate thus increasing its speed.

and field is from +ve plate to -ve plate.

A -> B

B is the negatively charged plate.

Ans: B

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v = 1.85c/ 100 = 5.55 x 10^6 m/s

Energy gain = q V

(9.109 x 10^-31) (5.55 x 10^6)^2 / 2 = (1.6 x 10^-19) V

V = 87.68 Volt

E = V/d = (87.68) / (0.897 x 10^-3)

E = 97750 N/C

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