Standing at the edge of a cliff 30.6 m high, you drop a ball.Later, you throw a
ID: 1574519 • Letter: S
Question
Standing at the edge of a cliff 30.6 m high, you drop a ball.Later, you throw a second ball downward with an initial speed of 11.6 m/s. Part A Which ball has the greater increase in speed when it reaches the base of the cliff, or do both balls speed up by the same amount? O O The first ball has the greater increase in speed The second ball has the greater increase in speed. Both balls speed up by the same amount Submit Reguest Answer Part B This question will be shown after you complete previous question(s). Provide Feedback Next )Explanation / Answer
Both balls speed up by the same amount,
Because The height to which it bounces h=e2h.
Here e is the coefficient of restitution, e=(h'/h)1/2.
So, height to which it bounces is depends upon the height of a cliff (h). So the speed is also same for both balls after bounce.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.