(13%) Problem 4: In the figure, the point charges are located at the corners of
ID: 1574694 • Letter: #
Question
(13%) Problem 4: In the figure, the point charges are located at the corners of an equilateral triangle 29 cm on a side da Ic ©theexpertta.com 25% Part (a) Find the magnitude of the electric field in NC at the location of qa given that q,-11.5 C and q,--5.8 C Grade Su Deductions Potential mmary E,1-11.85 * 106 890 92% sin0 cotana 78 9 HOME 415161 coso asin) atanacotan)sinh() cosh0)tanh) cotanh O Degrees O Radians Submissions Attempts remaining: 1 (4% per attempt) acosO detailed view END 490 BACKSPACE DEL CLEAR 2 4% Submit Hint Feedback I give up! Hints: 400 deduction per hint. Hints remaining: 4 Feedback: 5% deduction per feedback. 25% Part(b) Find the direction of the electric field at qa in degrees above the negative x-axis with origin at ga. 25% Part (c) What is the magnitude of the force in N on qa, given that q,-1.5 nC? 25% Part (d) What is the direction of the force on qa in degrees above the negative x-axis with origin at q?Explanation / Answer
given side of triangle, a = 0.29 m
assume that the origin is at qc with x axis pointing towards right
also, i and ja re unit vectors in x and y direction
then
a. Electric field at qa = Ea
Ea = k(qc(cos(60)i + sin(60)j) + qb(-cos(60)i + sin(60)j))/a^2
qb = 11.5 micro C
qc = -5.8 micro C
hence
Ea = -923626.634958i + 527091.276j N/C
hence
|Ea| = 1.06344*10^6 N/C
b. direction of electric field above -ve x axis = theta
now, tan(theta) = 527091.276/923626.634958
theta = 29.7123 deg
c. Fa = qa*Ea = 1.59516*10^-3 N
d. direction of force = direction of electric field = 29.7123 deg above -ve x axis
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.