part b I got the answer it\'s E = 1.3x10^7N/C Part c. calculate the potential di

Question

                                    part b I got the answer it's E = 1.3x10^7N/C

    Part c.    calculate the potential difference between the inner and outer walls of the membrane express your answer using two significant figures.                                     please answer part c this is due today thanks.

Constants I Periodic Table Cell Membranes and Dielectrics Many cells in the body have a cell membrane whose inner and outer surfaces carry opposite charges, just like the plates of a parallel-plate capacitor. Suppose a typical cell membrane has a thickness of 8.5x 10 m, and its inner and outer surfaces carry charge densities of in the cell membrane has a dielectric constant of 5.5

Explanation / Answer

potential = electric field * thickness

= 1.3*107 * 8.5*10-9

=0.11 volt

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