In a rectangular coordinate system, a positive point charge q = 7.50 nC is place
ID: 1574771 • Letter: I
Question
In a rectangular coordinate system, a positive point charge q = 7.50 nC is placed at the point x=0.230 m , y=0, and an identical point charge is placed at x= -0.230 m , y=0. Find the x and ycomponents and the magnitude and direction of the electric field at the following points.
Find the x and y components of the electric field at x= 0.230 m , y= -0.350 m .
Find the magnitude of the electric field at x= 0.230 m , y= -0.350 m .
Find the directiion of the electric field at x= 0.230 m , y= -0.350 m .
Explanation / Answer
a)
E1 = k*q1/r1^2
= 9*10^9*7.5*10^-9/0.35^2
= 551 N/C (towards -y axis)
E2 = k*q2/r2^2
= 9*10^9*7.5*10^-9/((2*0.23)^2 + 0.35^2 )
= 202 N/C (below +x axis)
Ex = E1x + E2x
= 0 + 202*2*0.23/sqrt((2*0.23)^2 + 0.35^2 )
= 161 N/c <<<<<<<-----Answer
Ey = E1y
= -551 N/c <<<<<<<-----Answer
b) |E| = sqrt(Ex^2 +Ey^2)
= sqrt(161^2 + 551^2)
= 574 N/c
c) direction : theta = tan^-1(Ey/Ex)
= tan^-1(-551/161)
= 73.7 degrees below +x axis
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