Need Help? A fish e counterclockwise from the x axs (C) If the fish maintains co

Question

Need Help? A fish e counterclockwise from the x axs (C) If the fish maintains constant acceleration, where is it att = 24 O s? In what direction is it moving? counterclock wise from the + x-axis Mayan kings and many school sports teams are named for the puma, cougar, or mou angle of 49 With what speed, in SI units, does it leave the ground to make this leap? untain lion Felis concolor, the best jumper among animals. It can jump to a height of 13.6 ft when leaving the ground a Type here to OLL F6 F4

Explanation / Answer

(a) Acceleration in x-direction ax = dVx/dt = (17 - 4)/19 = 0.684 m/s2

Acceleration in y-direction ay = dVy/dt = (-6 - 1)/19 = -0.368 m/s2

(b) Direction with respect to unit vector i, = arctan(-0.368/.684) = -28.31 degrees (below the x-axis).

(c) Distance travelled in x-direction in 24 s is given by sx = uxt + 1/2*axt2

sx = 4*24 + 1/2*0.684*242 = 293 m

Distance traveled in y-direction in 24 s is given by sy = uyt + 1/2*ayt2

sy = 1*24 + 1/2*(-0.368)*242 = -81.98 m

With respct to the rock, x -position of fish is 12 + 293 = 305 m

With respect to rock, y-position of fish is -2.4 - 81.98 = -84.38 m

Position at t = 24 s is therefore, P = 305 i - 84.38 j

Direction with x-axis is arctan(-84.38/305) = -15.46 degrees (below the x-axis)

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