Estimate how much (surface) charge it takes to keep a party balloan filled with

Question

Estimate how much (surface) charge it takes to keep a party balloan filled with air stuck to the ceilling (6 pt) Hint: There is not exact answer here. Make some reasonable &simplifying; assumptions such as all the charges on the balloon congregate at the same place. Il Based on book problem 21.79 (page 718): There is a positive charge distribution along the x-axis from the origin to a-0.1 m. Assume the total distributed charge is Q-2.0 C In addition, there is a point charge of q-0.50 C a distance of r-olm from the edge of the linear charge distribution (as shown). a. Determine the electric field at a point x along the x-axis. The point"xis to the right of the positive charge distribution. Make a plot of this electric field fram 0.25 m to 25 m. 14 pt) (Extra credit 2 pts) Calculate the electric field along the y-axis b. II Based on book problem 21.29 A electron is projected with an initial speed v-150,000 m/sec into a uniform field between two parallel plates. Assume the field is uniform and directed vertically down and that the field outside is zero. The electron enters the field midway between the plates as shown. If the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field and the charge density on each plate. ISpt) K-2.00 cm- 1.00 cm

Explanation / Answer

consider the motion of electron along the horizontal direction

Vo = horizontal velocity = 150,000 m/s

X = horizontal distance travelled = 2 cm = 0.02 m

t = time of travel

using the equation

t = X/Vo = 0.02/150,000 = 1.33 x 10-7 sec

Consider the motion along the vertical direction

Vo = initial velocity = 0 m/s

Y = vertical displacement = 0.5 cm = 0.005 m

a = acceleration = ?

t = 1.33 x 10-7 sec

Using the equation

Y = Vo t + (0.5) a t2

0.005 = 0 (1.33 x 10-7) + (0.5) a (1.33 x 10-7)2

a = 5.65 x 1011 m/s2

acceleration is given as

a = qE/m = 5.65 x 1011

(1.6 x 10-19) E/(9.1 x 10-31) = 5.65 x 1011

E = 3.2 N/C

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