HW-02 1d motion Brgin Date: 1/21/2018 10000 AM- -De Date: 1/31/2018 1 00 PM End

Question

HW-02 1d motion Brgin Date: 1/21/2018 10000 AM- -De Date: 1/31/2018 1 00 PM End Date: 31/2018 12:00:00 AM (8%) Problem 12: Two stones are separated by vertical distance rin nieters) from each other. Oue stone is thrown down with an isitial velocity vo-23 m's and the other is thrown up from the ground with an initial w 26 m's at the same tisme the other is thrown 33% Part (a) How far, in meters, must they be separated so they hit the grond at the samse time? uctioes cotano | asato | acosD detailed viess cosh) tanh) cotanb) .Degrees &Radians; grve 33% Part (b) What is the impact velocity, iii meters per second, of the first stone? 33% Part (c) what is the impact velocity, in meters per seoud of the second tou?

Explanation / Answer

here,

let the time taken to hit the ground be t and the height be h

for first stone

initial speed , u1 = - 23 m/s

h = u1 * t - 0.5 * g * t^2

- h = - 23 * t - 0.5 * 9.81 * t^2 ....(1)

and

for seccond stone

initial speed , u2 = 26 m/s

0 = u2 * t - 0.5 * g * t^2

0 = 26 * t - 0.5 * 9.81 * t^2 .....(2)

from (1) and (2)

h = 260 m

t = 5.3 s

a)

the sepration between the stones is 260 m

b)

the impact velocity of 1 , v1 = u1 - g * t1

v1 = - 23 - 9.81 * 5.3 = - 75 m/s or 75 m/s downwards

c)

the impact velocity of 2 , v2 = u2 - g * t1

v2 = 23 m/s downwards

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