Children playing in the neighborhood park on a cold day find a section of PVC pi

Question

Children playing in the neighborhood park on a cold day find a section of PVC pipe 49.0 cm long and open at both ends, and they begin blowing through it to produce trumpet-like sounds. The pipe is initially at 2.20°C and warms to 27.0°C when warm air is blown through it. What is the change in the fundamental frequency of the pipe after it warms? The coefficient of thermal expansion for PVC is 54 × 10-6°C-1. (Assume the change in the speed of sound as a function of temperature is negligible but that the length of the tube changes due to thermal expansion. Take the speed of the sound in air to be 343 m/s.) 13.29 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Hz Need Help?ReadIt

Explanation / Answer

L = 49 cm = 0.49 cm

L' = L + L*alfa*dT

= 0.49 + 0.49*54*10^-6*(27 - 2.2)

= 0.490656 m

change in fundamental frequency = f - f'

= v/(2*L) - v/(2*L')

= 343/(2*0.49) - 343/(2*0.490656)

= 0.468 Hz

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.