a monotomic ideal gas is initially at a pressure of 1.20 atm in a 1.20-L cylindr

Question

a monotomic ideal gas is initially at a pressure of 1.20 atm in a 1.20-L cylindrical container with a piston on one side. It is compressed to a volume 0.340 L.
Determine the final pressure, assuming the process is either (i) adiabatic or (ii) isothermal. adiabatic: _________Pa isothermal: __________Pa a monotomic ideal gas is initially at a pressure of 1.20 atm in a 1.20-L cylindrical container with a piston on one side. It is compressed to a volume 0.340 L.
Determine the final pressure, assuming the process is either (i) adiabatic or (ii) isothermal. adiabatic: _________Pa isothermal: __________Pa
Determine the final pressure, assuming the process is either (i) adiabatic or (ii) isothermal. adiabatic: _________Pa isothermal: __________Pa

Explanation / Answer

Ans:-

Given data Pi = 1.20atm , vi = 1.20L Vf = 0.340L

I]In adiabatic process

PV = const

Pivi = PfVf

Pf = Pi Vi/Vf = 1.20*1.20/0.340 =4.24atm

Pf =4.24*1.013*10^5 = 4.29*10^5Pa

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