2. + 0/1 points | Previous Answers KatzPSEf1 20.P.071.MI. DMy Notes + Ask Your T
ID: 1575686 • Letter: 2
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2. + 0/1 points | Previous Answers KatzPSEf1 20.P.071.MI. DMy Notes + Ask Your Teache A 0.560-m3 container holding 3.20 mol of ozone (03) is kept at a temperature of 300 K. Assume the molecules have radius r = 2.50 x 10-10 m. What are the following? (a) the mean free path 6.543E-17 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m (b) mean free time between collisions for an ozone molecule in the container 1.798E-19 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. S Need Help? Read It Master ItExplanation / Answer
A) mean free path = 1/(d^2*n)
d- diameter of the molecule
n- number of molecules per unit volume
Mfp = 1/(* (5*10^-10)^2*3.2*6.023*10^23/0.56)
= 3.6493e^-6
B)mean free time = mfp/average speed (avg speed = 8RT/M=483.57)
= 3.6493e^-6/483.57
= 7.5466e^-9s
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