Question : Find the magnitude and direction of the electric field this combinati

Question

Question: Find the magnitude and direction of the electric field this combination of charges produces at point P , which lies 6.00 cm from the -q2 charge measured perpendicular to the line connecting the three charges. Assume that q1 = 5.30 C and q2 = 2.35 C.

Away from -q2 or toward -q2?

Part A Three negative point charges lie along a line as shown in the figure (Figure 1). Find the magnitude and direction of the electric field this combination of charges produces at point P, which lies 6.00 cm from the -g2 charge measured perpendicular to the line connecting the three charges. Assume that h = 5.30 C and q2-2.35 C N/C gure 1 of 1 Submit -q Part B 8.00 cm 6.00 cm O away from -g2 toward-Q2 8.00 cm Submit Request Answer -9 Provide Feedback Next >

Explanation / Answer

angle made by q1 at point P = tneta = tan^-1(8/6) = 53.13

r1 = sqrt(8^2+6^2) = 10 cm = 0.1 m

E1x = -k*q1*costheta/r1^2 = -9*10^9*5.3*10^-6*cos53.13/0.1^2

E1x = -28.6*10^5 N/C

E2x = -k*q2/x^2 = -9*10^9*2.35*10^-6/0.06^2 = -58.75*10^5 N/C

Ex = E1x + E1x + E2x = -115.9*10^5 N/C = --116*10^5 N/C

part A

magnitude E = 116*10^5 N/C N/C

part B

direction = toward -q2

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