The lines show the equipotential contours in the plane of three point charges, Q

Question

The lines show the equipotential contours in the plane of three point charges, Q1, Q2, and Q3. The values of the potentials are in kV as indicated for the +5, 0, and 5 kV contours, The positions of the charges are indicated by the dots. Q1 Q2 olts Q3 cm1 2 3 4 5 The letters are on the equipotential contours Calculate the size of the force on a charge of 4.80x10-19 C at k. 9.60 10-14)N First calculate the electric field in the same way as you did for the previous problem. Then, remember the relation between force and E-field. Submit Answer Incorrect. Tries 4/12 Previous_Tries

Explanation / Answer

Force on charge at k,

F = qE

where, E = V / d

and d =  perpendicular distance between the equipotentials either side of k

d = 12.5 mm

equipotentials either side of k = (-1 kV , +1 kV)

so, V = 2 kV

E = 2*10^3 / 12.5*10^(-3)

E = 0.16*10^6 N/C

Force on charge at k,

F = 4.8*10^(-19) * 0.16*10^6

F = 7.68*10^(-14) N

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