The center-to-center distance between a 100-glead sphere and an 400-g lead spher

Question

The center-to-center distance between a 100-glead sphere and an 400-g lead sphere is 0.120 m.A 1.20-g object is placed 0.0800 m from the center of the 400-g sphere along the line joining the centers of the two spheres.

Part A
Ignoring all sources of gravitational force except the two spheres, calculate the magnitude of the gravitational force exerted on the object.

Part B

Determine the gravitational potential energy per gram at the position of the object.

Part C

How much work is needed to bring the object 0.0400 m closer to the 400-g sphere?

Explanation / Answer

Part A:-

F= GM1M2/R^2

Object 1.20 grm in wegiht is in the line of two other objects i.e 100 gm and 400 gm', both of these will try to attract the 1.20 mass to itself . the net resultant force will be the susbstraction of both

F1= G 400*1.20/64

F2=G100*1.20/16

Net force will be G(480/64-120/16)=0*G =0 so the force will be nullified

part B F1 and F2 is the potential energy on the obeject

F.ds= work,

now the net forces will change

The equation will change to G(480/16-120/64)=(30-1.875)*G=28.125*G*4 is the answer.

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