Two identical conducting spheres, fixed in place, attract each other with an ele
ID: 1577039 • Letter: T
Question
Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.120 N when ther center-to-center connected by a thin conducting wire. When the wire is removed, the spheres have a net separation is 55.0 cm. The spheres are then positive charge and repel each other spheres, and whiat was the intial posktive charge on the other? (Hint: Use charge conservation and solve for one of the intial charges, You wil with an electrostatic force of 0.0320 N. What was the and negative charges, Include the sign of the value in your anawer) end up with a quadratic equation. The solutions give you the postive initial negative charge intial positive charge Additional MaterialsExplanation / Answer
6.
let the charge on the spheres be Q1 and Q2
Given that :
F = k Q1 Q2/r2
0.120 = (9 x 109) Q1 Q2/(0.55)2
Q1 Q2 = 4.03 x 10-12
since charges are opposite in nature , hence
Q1 Q2 = - 4.03 x 10-12
Q = charge on each sphere after connecting through a wire = (Q1 + Q2)/2
Given that :
F = k Q1 Q2/r2
0.032 = (9 x 109) Q2/(0.55)2
Q = 1.04 x 10-6
(Q1 + Q2)/2 = 1.04 x 10-6
(- 4.03 x 10-12 /Q2) + Q2 = 2.08 x 10-6
Q2 = 3.3 x 10-6
Q1 = - 1.22 x 10-6 C
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