Chapter 20 Homework Problem 20.59 8 of 11 A parallel-plate capacitor has plates

Question

Chapter 20 Homework

Problem 20.59

8 of 11

A parallel-plate capacitor has plates of area 3.84×104 m2 .

Part A

What plate separation is required if the capacitance is to be 1450 pF ? Assume that the space between the plates is filled with air? (Dielectric constant for air is 1.00059)

Express your answer using three significant figures.

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Part B

What plate separation is required if the capacitance is to be 1450 pF ? Assume that the space between the plates is filled with paper. (Dielectric constant for paper is 3.7)

Express your answer using two significant figures.

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Next

A parallel-plate capacitor has plates of area 3.84×104 m2 .

Part A

What plate separation is required if the capacitance is to be 1450 pF ? Assume that the space between the plates is filled with air? (Dielectric constant for air is 1.00059)

Express your answer using three significant figures.

d = m

SubmitRequest Answer

Part B

What plate separation is required if the capacitance is to be 1450 pF ? Assume that the space between the plates is filled with paper. (Dielectric constant for paper is 3.7)

Express your answer using two significant figures.

d = m

SubmitRequest Answer

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Explanation / Answer

a)

here by using the formula

C = e0 * k * A / d

e0 = 8.854 * 10-12F/m

k = 1.00059

then by putting the values in the formula

1450 * 10-12 = 8.854 * 10-12 * 1.00059 * 3.84 * 10-4 / d

d = 2.34 um

b)

here also by using the same formula

C = e0 * k * A / d

1450 * 10-12 = 8.854 * 10-12 * 3.7 * 3.84* 10-4 / d

d = 8.67um

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