The Expert TA Human. x e Chegg Study I Guided Solut | + LTX | usq45tx theexpertt

Question

The Expert TA Human. x e Chegg Study I Guided Solut | + LTX | usq45tx theexpertta.com/Common/TakeTutorialAssignment.aspx Class M l Help Assignment-2 Begin Date: 262018 12:01:00 AM Due Date: 2'13 2018 11:59:00 PMEnd Date: 2/14 2018 11:59:00 PM (27%) Problem 5: In the figure, these three resistors are connected to voltage source so that R,-4.5 11 and R1-11 are in parallel with one auother and thal combination is in series with RI-a 75 . Assignment Status 12.0 V R2 Click here for detailed view Problem Status Completed Completed Complete Completed ©theexpertta.com 50% Part (a) Calculate the power being dissipated by the third resistor P, in watts. Grade Summary 6 Completed 100% cos0 laul ) ( - Attempts remmaining: 1U per attempt) atanacolan ti coshan uh detalled view Degrees O Radians Subcnat I TI Hints: 1% deduction pet hit. Hints remaining: 3 Feedback: 0% deduction per feedback. 50% Part(b) Find the total power supplied by the source, in watts. lype here to search 2/10/2018

Explanation / Answer

R2 and R3 are in parallel, so the resistance there is

1/Rp = 1/4.5 + 1/11

Rp = 3.19 Ohms

That Rp is in series with R1, so net Resistance in the circuit is

0.75 + 3.19 = 3.94 Ohms

Then apply V = IR to find the current in the circuit

12 = I(3.94)

I = 3.05 A

The voltage in the parallel portion is from

V = IR

V = (3.05)(3.19)

V = 9.72 V

The current through R3 is from V = IR

9.72 = I(11)

I = 0.88 Amps

power through that Resistor is from

P = I^2R

P = (0.88)^2(11)

P = 8.58 Watts

B)

P = IV

P = (3.05)(12)

P = 36.6 W

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.