1.1 The electric flux through an enclosed surface is determined by (5 points) A.
ID: 1578650 • Letter: 1
Question
1.1 The electric flux through an enclosed surface is determined by (5 points) A. Charges inside the surface B. Charges outside the surface C. Both charges inside and outside 1.2 Electric field is the electric force divided by the test charge, so electric field is determined by the test or False charge? (5 points) True 1.3 A solid conducting sphere is given a positive charge Q. How is the charge Q distributed in or on the sphere? (5 points) It is concentrated at the center of the sphere It is uniformly distributed throughout the sphere. Its density decreases radially outward from the center It is uniformly distributed on the surface of the sphere only. Its density increases radially outward from the center. C. e. 1.4 For a capacitor, its charge is higher if the applied voltage is higher. However, the capacitance is not determined by the charge and applied voltage. True or False 1.5 The net electric flux through a closed surface is: (5 points) (which statement is true?). infinite only if there are no charges enclosed by the surface. infinite only if the net charge enclosed by the surface is zero zero if only negative charges are enclosed by the surface. zero if only positive charges are enclosed by the surface. zero if the net charge enclosed by the surface is zero C.Explanation / Answer
(1.1)
In accordance with Gauss's law, the electric flux enclosed in a closed surface is 0 times the charge enclosed in the surface.
The electric flux through a surface depends on the total charge enclosed by the surface; it does not depends on charges outside.
Thus, the correct option is (A)
-----------------------------------------------------------------------------------------
(1.2)
Electric field is ratio of force to magnitude of charge. A aositive test charge will experience a force in the direction of the electric field. so, the electric field can be determined by a postive test charge.
Given statement is True.
--------------------------------------------------------------------------------------------------
(1.3)
In the case of solid conducting sphere, the charge is enclosed on the surface of the sphere only. The net charge inside is cancelled out.
Correct option is (d)
--------------------------------------------------------------------
(1.4)
For a capacitance, its charge is higher if applied voltage is higher. So, we can determine capacitance from this information.
Otherwise, the capacitance is determined by area of plates and distance between the plates. However, this is the not case here.
Thus, the given statement is False.
-----------------------------------------------------------------------------
(1.5)
In accordance with Gauss's law, the electric flux enclosed in a closed surface is 0 times the charge enclosed in the surface. If net charge enclosed is zero then the flux enclosed is zero.
Thus, the correct option is (e)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.