ahle to use Casslaw so find the electric felds of charged sphere, cylimdex, pane
ID: 1578828 • Letter: A
Question
ahle to use Casslaw so find the electric felds of charged sphere, cylimdex, pane, or ey lismdrical shel. ectric potential energy U-U--w. U--w ectric potential v- loulating potential from field v--f·E-di v-v-- · field froen potetial: Ev ial energy: For two charges U -, for mukiple charges U potential of comtinuous charge v- to find the elestric potential at a point by muhiple changes: he able to find the pesential of charged rod, and disk calculate the potential energy of a point charge sy stem 2. (30 pts) (1) Given the electric flux into the cylinder side surface to 8 Nm2/C and out of the cylinder top and bottom surfaces to be 6 and 4 Nm/C, respectively. Find the electric charge inside the cylinder. (2) For a long cylinder with a radius of 10 em and is uniformly charged with the charge line density 100 nC/m, what is the electric field inside the cylinder at a point with the radial distance of 4 cm from the axis?Explanation / Answer
2. (1) total flux = - 8 + 6 + 4 = 2 N m^2 / C
from Gauss law, net flux = Qin / e0
2 = (Qin) / (8.854 x 10^-12)
Q = 17.7 x 10^-12 C
2) from Gauss law for long cylinder,
E ( 2 pi r L ) = Qin / e0
Qin = lambda L r^2 / R^2
E (2 pi r L ) = ( lambda L r^2 / R^2) / e0
E = lambda r / (2 pi e0 R^2)
E = (100 x 10^-9)(0.04) / (2 x pi x 8.854 x 10^-12 x 0.10^2)
E = 7190.2 N/C
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