Name: PROBLEM 5-8 points The circuit in the picture consists of a24 volt battery

Question

Name: PROBLEM 5-8 points The circuit in the picture consists of a24 volt battery, a 4.0 F The switch starts open and remains open until part (c). n A. [2 points] (a) With the switch open, there is an instant in time when the voltage across the capacitor is 18.0 V (the top plate being at a higher potential than the bottom plate, as you would expect). At this instant, calculate the current through the resistor RA. After the capacitor is fully charged, the switch is closed. This causes the capacitor to begin to discharge. Again, there is an instant in time when the voltage across the capacitor is 18.0 V. At this instant. RB. 2 points) tb) ...calculate the current through the resistor Rp [2 points] ()... calculate the current in the middle branch of the circuit, where the capacitor is. [2 points] (d) After this instant in time, the capacitor continues to discharge. Select all the true statements about this, describing the changes that take place after the instant when the capacitor voltage has dropped to 18 V. We assume the battery never runs out of charge! I I The current in the circuit eventually drops to zero everywhere I 1 The current through resistor A increases gradually to a constant value above the value from (a) I 1 The current through resistor B increases gradually to a constant value above the value from (b) I 1 The capacitor voltage eventually drops to 0 V and then remains constant. I 1 The capacitor voltage eventually drops to 8 V and then remains constant. [ 1 The capacitor voltage eventually drops to 16 V and then remains constant.

Explanation / Answer

a)When the voltage across capacitor is

Vc = 18 V

the voltage across RA will be:

VA = 24 - 18 = 6 V

IA = VA/RA = 6/2 = 3 A

Hence, IA = 3 A

b)Since C and Rb are in parallel,

VB = 18 V

IB = 18/4 = 4.5 A

Hence, IB = 4.5 A

c)I = 3 + 4.5 = 7.5 A

Hence, I = 7.5 A

d)The correct ones are:

second statement

fourth statement

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