QUESTION 1 5points Suppose after charging a 6.3 F capacitor to 10 V, you connect

Question

QUESTION 1 5points Suppose after charging a 6.3 F capacitor to 10 V, you connect it to the second uncharged capacitor of 2.6 -what voltage will your voltmeter read across the second capacitor after repeating the charge sharing process two times? Express the answer with one decimal place. QUESTION 2 5 points Save Answer A 4.8 microfarad capacitor, C1, was charged to voltage 27 V and connected in parallel to an uncharged capacitor C2. What is the capacitance of the second uncharged capacitor C2, if the final voltage is 13.3 V? Express the answer to three significant figures. Tip: you can use scientific/exponential notation to represent numeric values. Eg, -0.0001 can be written as 1.0e-4 or as 1.0E-4. Spaces are not allowed

Explanation / Answer

Question 1.

V = (C1V1 + C2V2) / (C1 + C2)

In first charge sharing with uncharged capacitor,
C1 = 6.3, V1 = 10 V, C2 = 2.6
Unconnected, V2 = 0
V = (6.3 * 10+ 2.6 * 0) / (6.3 + 2.6) = 7.08 volts
Take this voltage and plug it in for V2 for the second sharing,

V = (6.3 * 10 + 2.6 * 7.08) / (6.3 + 2.6) = 9.2 V

Question 2.

Total capacitance of parallel-connected capacitors is equal to the sum of the individual capacitances.

Q=CV

Final voltage= 13.3 V, total capacitance= C1+C2=4.8+C2

Total charge= charge of capacitor C1= 4.8X27 V= 129.6 microcoulombs

Now,

129.6=(4.8+C2)*13.3

C2= 4.944 microfarad

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