In the figure, a conducting rod of length L = 32.0 cm moves in a magnetic field

Question

In the figure, a conducting rod of length L = 32.0 cm moves in a magnetic field B of magnitude 0.360 T directed into the plane of the figure. The rod moves with speed v = 7.00 m/s in the direction shown.

[The figure shows a horizontal rod with length L moving downwards with velocity v. The left and the right ends of the rod are labeled as a lowercase and b lowercase, respectively. Magnetic field of magnitude capital B is present, directed into the page.]

When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?

What is the magnitude Vba of the potential difference between the ends of the rod?

What is the magnitude E of the motional emf induced in the rod?

Explanation / Answer

for equlibrium,

E = v B = 7 x 0.360 = 2.52 V/m Or N/C .....Ans

Vba = E.L  

Vba = (2.52)(0.32) = 0.806 Volt ....Ans

and Vba = induced emf

inducef emf = 0.806 Volt ....Ans

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