(9%) Problem 3: A student pushes a baseball of m = 0.19 kg down onto the top of
ID: 1580145 • Letter: #
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(9%) Problem 3: A student pushes a baseball of m = 0.19 kg down onto the top of a vertical spring that has its lower end fixed to a table, compressing the spring a distance of d = 0.18 meters. The spring constant of the spring is k= 570 Nm. Let the gravitational potential energy be zero at the position of the baseball in the compressed spring Randomized Variables m=0.19kg k 5 70 N/m d= 0.18 m 33% Part (a) The ball is then released. What is its speed, v, in meters per second. Just after the ball leaves the spring? Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 10 (0%) per attempt) detailed view sinO |( tan() acosO atan acotan sinh() tanh)cotanh( coso cotanasinO cosh) 0 Degrees Radians Submit Hint I give up! Hints: 000 deduction per hint. Hints remaining: 1 Feedback: deduction per feedback. 33% Part (b) what is the maximum height, h, in meters, that the ball reaches above the equilibrium point? ) 33% Part (c) What is the ball's velocity in meters per second, at half of the maximum height relative to the equilibrium point? -Explanation / Answer
(a) 1/2 mv2= 1/2 kx2
1/2(0.19)v2=1/2 (570)(0.18)2
v=9.86 m/s
(b) V2=Vo2+2gh
0=(9.86)2+2 (-9.8)h
h= 4.96 m
(c)V2=Vo2+2gh
V2=(9.86)2+2(-9.8)(4.96/2)
V=6.97m/s
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