At time t 22.3s, what is the x-component of the dog\'s velodity? Express your an
ID: 1580640 • Letter: A
Question
At time t 22.3s, what is the x-component of the dog's velodity? Express your answer using two significant figures. Constants Adog running in an open field has components of velocity t 2.7 m/s and e, -1.5 m/s at time t 10.9 s. For the time nterval from t1 10.9 s to t2 22.3s, the average acceleration of the dog has magnitude 0.54 m/s and direction 34.0 measured from the+-axis toward the +y-axis m/s Submit Part B A time t2 22.3s, what is the ycomponent of the dog's velocity? Express your answer using two significant figures. m/s Submit Part C What is the magnitude of the dog's velocity? Express your answer using two significant figures m/s SubmitExplanation / Answer
given
ax = 0.54*cos(34) = 0.448 m/s^2
ay = 0.54*sin(34) = 0.302 m/s^2
A) vx = vox + ax*delta_t
= 2.7 + 0.448*(22.3 - 10.9)
= 7.81 m/s
B) vy = voy + ay*delta_t
= -1.5 + 0.302*(22.3 - 10.9)
= 1.94 m/s
C) v = sqrt(vx^2 + vy^2)
= sqrt(7.81^2 + 1.94^2)
= 8.05 m/s
D) direction : theta = tan^-1(vy/vx)
= tan^-1(1.94/7.81)
= 13.9 degrees
3.10)
A)
let t is the time taken.
use, y = (1/2)*g*t^2
t = sqrt(2*y/g)
= sqrt(2*9/9.8)
= 1.355 s
so, vo = x/t
= 1.75/1.355
= 1.29 m/s
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