Before Collision After Map im nm Vv 0.750v v\".nnal = ? n,fina \' vo particles a

Question

Before Collision After Map im nm Vv 0.750v v".nnal = ? n,fina ' vo particles approach each other with equal and opposite speed v. The mass of one particle is m, and the mass of the other particle is nm, where n is just a unitless number. Snapshots of the system before, during, and after the elastic collision are shown above. After the collision the first particle moves in the exact opposite direction with speed 0.750v, and the speed of the second particle is unknown. What is the value of n? Number

Explanation / Answer

By the conservation of momentum we have

m1u1 + m2u2 = m1v1 + m2v2

mv + (nm)*(-v) = m*(-0.75v) + nmv2

v - nv = -0.75v + nv2 -------(1)

Velocity of approach = velocity of recess

V2-v1 = u1 - u2

v2 - (-0.75v) = v - (-v)

v2 = 1.25v -----(2)

v - nv = -0.75v + 1.25nv

1 - n = -0.75 + 1.25n

1.75 = 2.25n

n = 0.78

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.