++-all 1:52 https://loncapa2.physics.sc.edu/res/sc/gblanpied/courses/usclib/hr)
ID: 1580957 • Letter: #
Question
++-all 1:52 https://loncapa2.physics.sc.edu/res/sc/gblanpied/courses/usclib/hr) curve e' ilerts til Assuming no energy losses, findthe current' n-Na.es Bzueli,K C-alue.e Curirutlicee Pill 'liilu x (8c27p1 10) A battery of = 2.70 V and internal resistance R = 0.400 is driving a motor. The motor is lifting a 2.0 N mass at constant speed v = 0.50 m/s. Assuming no energy losses, find the current i in the circuit. Enter the lower current. Enter the higher current. Suamlt Answer Tles C/99 Find the potential difference V across the terminals of the motor for the lower current Suaml Answer Tles /99 Find the potential difference V across the terminals of the motor for the higher current. SLAMIH AnswerTrles .99 Discuss the fact that there are two solutions to this problem.Explanation / Answer
(1) Power need to lift 2 N mass with velocity of 0.5 m/s
Power = 2*0.5 = 1 W
Power loss in the resistance = I2R = 0.4I2
Availabel power = 2.7 I
where I is the current in the circuit
0.4I2 + 1 = 2.7I
I = 0.393, 6.35 A
Lower current I = 0.393 A
(b) maximum current
I = 6.35 A
(c) Potential drop in the resistance = IR = 0.393*0.4 = 0.16
hence the potential across the motor = 2.7 - 0.1572 = 2.54 A
(d) In this case potential drop in the resistance = IR = 6.35*0.4 = 2.54
Hence the potential drop across the motor = 0.16
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.