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Awarehouse worker is pushing a 90.0 kg crate with·horizontal force of 279 N at a

ID: 1581087 • Letter: A

Question

Awarehouse worker is pushing a 90.0 kg crate with·horizontal force of 279 N at a speed of v-0860 m/s toon the wireose nor, hinonan·ngs noteana 0.75 m long and where the coefficient of kinetic friction between the crate and fooe is 0.357 are hoe tht- ta) Determine the magneude and direction of the net force acting on the crate hle is pushed over the rough secton ee the floor. magnitude (b) Determine net work done on the crate whle·is puted over the ro section or the no (c) Find the speed ofthe crace when·reaches the end of the rough surface

Explanation / Answer

a)Friction force = u*mg

=0.357*90*9.81

=315.195 N (towards left, opposite to the direction of motion of the box)

b)Work done on the box = Work done by the man on the box - work done by friction on the box

= (279-315.193)*0.75

= -27.1447 J

c)let the speed of the crate be v.so,

0.5mv^2 = 0.5*m*vi^2 + Work done

or 0.5*90*v^2 = 0.5*90*0.86^2 - 27.1447

or v=0.369 m/s

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