A 72.0 kg ice hockey goalie, originally at rest, catches a 0.150 kg hockey puck

Question

A 72.0 kg ice hockey goalie, originally at rest, catches a 0.150 kg hockey puck slapped at him at a velocity of 27.0 m/s. Suppose the goalie and the ice puck have an elastic collision and the puck is reflected back in the direction from which it came. What would their final velocities (in m/s) be in this case? (Assume the original direction of the ice puck toward the goalie is in the positive direction. Indicate the direction with the sign of your answer.)

puck ..................m/s

goalie.................. m/s

Explanation / Answer

m1 u1 + m2 u2 = m1 v1 + m2 v2

0 + (0.150 * 27) = 72 v1 + 0.15 v2

72 v1 + 0.15 v2 = 4.05 ----------------(1)

v2 - v1 = u1 - u2

v2 - v1 = -27 ---------------(2)

solving the above equations

v1 = 0.112 m/s

v2 = -26.88 m/s

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