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Standard Exardiss Parallel Plate Capacitor and Dielectric In the circuit shown i

ID: 1581567 • Letter: S

Question

Standard Exardiss Parallel Plate Capacitor and Dielectric In the circuit shown in the figure below, the batteries have negligible internal resistance. 7.00V Interactive Exemple Current Div 500 V 1.00 3.00 Standard Exerdise Tipler6 21.P.032. 2.00 Sandard Exeraise Tipler6 23.P.065 1) Find the current in each branch of the circuit. andard Exerase Tipler6 25.P.086 A Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. Slandard Exurdiso Tipler6 23.P.028 2) 122 Tipler6 24.P.042. A Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. 3) 3 A Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. 4) Find the potential difference between point a and point b. Submit You currently have 0 submissions for this question. Only 3 submission are allowed. You can make 3 more submissions for this question. 5) Find the power supplied by each battery 5v W Submit

Explanation / Answer

let

R1=1 ohm, R2=2 ohm, R3=3 ohm


and

current through R1 is I1


current through R2 is I2


current through R3 is I3


and

V1=7v and v2=5v

1)


by using Kirchhoff's laws


V1-I2*R2 -I3*R3+V2=0


7-I2*2-I3*3+5=0 ----(1)


and


v2-I1*R1-I3*R3=0


5-I1*1-I3*3=0 ---(2)


and


I1+I2=I3 ------ (3)


by sloving above equations(1), (2) and (3)


===>


I1= 1A


I2=3 A


I3=2 A


==>


1) I1=1A

2) I2=3 A

3) I3=2 A


4)


Vab=5+I3*R3

=5+2*3


=11 v


5)


power, P=V*I


at v1=7 v


P1=v1*I2


P1=7*3


P1=21 W


and


at V2=5 v

P2=V2*I3

P2=5*2


P2=10 W

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