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(696) Problem 14: A 1.25-N1 voltmeter is placed in parallel with a 80.5-kf2 resi

ID: 1581585 • Letter: #

Question

(696) Problem 14: A 1.25-N1 voltmeter is placed in parallel with a 80.5-kf2 resistor which is in a circuit. > 33% Part (a) What is the resistance, in kilohms, ofthe combination? Grade Summary Deductions Potential 0% 100% 7 8 9 sin0 cotan0 asin acos0 atan0 acotan sinhO cosh0 tanh cotanh0 tan Submissions Attempts remaining: Z (490 per attempt) detailed view cosO *1 2 3 END Degrees Radians CLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0%, deduction per feedback. - 33% Part (b) If the voltage across the combination is kept the same as it was across the 805-K2 resistor alone, what is the percent increase in the current through this part of the circuit? - 33% Part (c) If instead the current through the combination is kept the same as it was through the 80.5-k resistor alone, what is the percentage decrease in voltage?

Explanation / Answer

a) Requ = 1 / ( 1/(1.25*106) + 1/(80.5*103))

= 75,629 ohms = 75.63 k.ohms

b) percent increase = (1/R2 - 1/R1) / (1/R1)

= [ (1/75,629 - 1/(80.5*103)) ] / [ (1 / (80.5*103) ) ]

percent increase = 6.44 %

c) percent decrease = (R2 - R1) / R1

= (75629 - (80.5*103) ) / ((80.5*103))

= 6.0 %