Jump to... Map do Sapling Learning A sphere of radius R 0.330 m and uniform char

Question

Jump to... Map do Sapling Learning A sphere of radius R 0.330 m and uniform charge density-453 nC/m lies at the center of a spherical charge or o e 14.3 nc, find the magnitude of the electric field at the following radial distances from the g shell of inner and outer radi 3.50R and 4.00R, respectively. If the conducting shell carries a total 3.85R 43484.08 NI C N/ C Incorrect. The electric field is only affected by the amount of char at distances s0.360R, not the full charge on the central sphere de 05R 50R 340.99 N/ C -161.35 N/ C O Previous # Try Again O Next 8 Exit about us en

Explanation / Answer

Here ,

for x = 0.360 * R

electric field = k * Qin / x^2

electric field = -9*10^9 * (4/3) * pi * (0.36* 0.33)^3 * 453 *10^-9 / (0.36* 0.33)^2

electric field = - 2028.83 N/C

the electric field at 0.36 * R is 2029 N/C inwards

b)

charge inside the sphere ,

Qin = -(4/3) * pi * (0.33)^3 * 453 *10^-9

QIn = -68.2 nC

for x = 2.05 R

electric field = k * Qin/d^2

electric field = 9*10^9 * 68.2 *10^-9/( 2.05 * 0.33)^2

electric field = -1341 N/C

the electric field is 1341 N/C inwards

c)

for x = 3.85 R

as the electric field is zero inside the conducting shell .

the electric field sis ZERO

d)

for x = 6.50 R

electric field = k * Qin/d^2

electric field = 9*10^9 * (- 68.2 + 14.3 ) *10^-9 /( 6.5* 0.33)^2

electric field = -105 N/C

the electric field is 105 N/C inwards

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