Problem 23.55-MC Constants Part A The veltnge acrass the terminals of a real bat

Question

Problem 23.55-MC Constants Part A The veltnge acrass the terminals of a real battery will be smalar than its amf due to what is caled the internal resislance of the batdery. We can model a real 1.5 V battery as a 1.5 V emf in series wilth a resistor, as shown in the figure(Figure 1) A typical battery has 1.0 intemal resistance due to imperfections thar Iimit current through the battery. when thara's no curren through tha battary, and thus no voltaga drap acrass the intarnal resistanon, the potential difference between its terrminals is 1.5 V, the value of the emf. How much current flows when this battery is connected to the 3,5 resistor? Express your answer using threc significant figures along with the correct unit. View Available Hint(s) IValue Units Submit Part B of the b ey? Hint: The potential di rence betwean th8rminals o the battery s given by the atten s minus the voltage What is the patentia dife ence between the termina across the internal eaistanca Express your answer using three significant figures. along with the correct unit Value Units Figure Submit PartC What paroontaga of tha battory's power is dissipatnd by the intamal resistance? Express your answer using three significant figures. 1.0 View Available Hint(s) 1.5 V

Explanation / Answer

A) I = V/Req

= V/(R + r)

= 1.5/(3.5 + 1)

= 0.333 A

B) V_terminal = V_emf - I*r

= 1.5 - 0.333*1

= 1.167 V

C) Pint/Pemf = I^2*r/(I*V_emf)

= 0.333^2*1/(0.333*1.5)

= 0.222

= 22.2%

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