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nt PRENTER VERSTON BACK Chapter 22, Problem 21 (910 turns, radius-0.065 m) is ro

ID: 1582292 • Letter: N

Question

nt PRENTER VERSTON BACK Chapter 22, Problem 21 (910 turns, radius-0.065 m) is rotating n a uniform magnetic field. At t-0 s, the normal to the col is pep de lar to the magnetic neid. At t·0.013s, the nonna' makes an angle of 45 with the field because the coil has made location of the coll. t one-eighth of a revolution. An average emf of magnitude 0045 V is induced in the coil. Find the magnitude of the magnetic fReld at the Number Unilts the tolerance is +/-6% By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor o answer this question 083& Sansnc A Righes Reserved. A Division of n es& SaI

Explanation / Answer

The EMF = d(magnetic flux)/dt

magnetic flux = B.A (where . is the dot product).

so,

initial flux = B.A = B*A

final flux = B.A = B*A*cos(45)

so, change in flux = (BA - BA*cos(45)

=BA*(1-cos(45))

so, EMF = d(flux)/dt

=BA*(1-cos(45))/(0.013)

or 0.045 = B*900*pi*0.065^2*(1-2^-0.5) / 0.013

or B = 1.67*10^-4 T