As shown in the figure below, a box of mass m = 58.0 kg initially at rest s push
ID: 1582302 • Letter: A
Question
As shown in the figure below, a box of mass m = 58.0 kg initially at rest s pushed a distance d = 100 m across a rough warehouse floor by an applied orce of FA a 218 N directed at an ang of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) 30° rough surface (a) work done by the applied force WA 18879 (b) work done by the force of gravity (c) work done by the normal force (d) work done by the force of friction Wr-5694900X Pay careful attention to the angle between the direction of the force of friction and the displacement vector. Do you recall how to determine the force of friction in terms of the normal force and the coefficient of friction? A good diagram showing all the forces and their components will help you determine a correct expression for the normal force needed in order to determine the force of friction. (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. wNec =Explanation / Answer
let's calculate the normal force
N = mg + F sin theta = 58 (9.8) + 218 sin 30 =677.4
work done by friction = (0.1) ( 677.4) (100m) =6774 J
Net work done = work done by applied force - work done by friction =18879 - 6774 J= 12105 J
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